engineering computer science MCQ #389

What is the S/N ratio for a channel with a capacity of 20000 bps and a bandwidth of 3000 Hz?

engineering computer science MCQ #389

  1. Question 1

    Q1. What is the S/N ratio for a channel with a capacity of 20000 bps and a bandwidth of 3000 Hz?

    • A) 7.04
    • B) 15
    • C) 31
    • D) 63

    Answer: 7.04

    Explanation: Using Shannon-Hartley theorem: C = B * log2(1 + S/N), 20000 = 3000 * log2(1 + S/N), S/N = 2^(20000/3000) - 1 = 7.04.