What is the efficiency of a stop-and-wait protocol with a packet size of 1000 bytes and a bandwidth of 1 Mbps?
Q1. What is the efficiency of a stop-and-wait protocol with a packet size of 1000 bytes and a bandwidth of 1 Mbps?
Answer: 0.2
Explanation: Efficiency = 1 / (1 + 2a), where a = propagation time / transmission time. Assuming a = 2, efficiency = 1 / 5 = 0.2.