A channel has a bandwidth of 20 MHz and uses QPSK modulation. What is the data rate?
Q1. A channel has a bandwidth of 20 MHz and uses QPSK modulation. What is the data rate?
Answer: 80 Mbps
Explanation: Data rate = bandwidth * log2(L), where L = 4 for QPSK, so 20 * log2(4) = 40 Mbps, but since it's QPSK, it's 2 * 40 = 80 Mbps (using 2 bits per symbol).