In a stop-and-wait protocol, the transmission time is 1 ms and the propagation time is 2 ms. What is the efficiency?
Q1. In a stop-and-wait protocol, the transmission time is 1 ms and the propagation time is 2 ms. What is the efficiency?
Answer: 1/3
Explanation: Efficiency = transmission time / (transmission time + 2 * propagation time) = 1 / (1 + 2*2) = 1/5, but since ack transmission time is negligible, it is 1 / (1 + 2*2) = 1/5.