A channel with a bandwidth of 4 kHz and an SNR of 30 dB has a maximum data rate of?
Q1. A channel with a bandwidth of 4 kHz and an SNR of 30 dB has a maximum data rate of?
Answer: 40 kbps
Explanation: Using Shannon's theorem, max data rate = 4000 * log2(1 + 10^(30/10)) = 4000 * log2(1001) ≈ 39865 bps or 40 kbps.