A channel has a bandwidth of 20 MHz and uses QPSK modulation. What is the maximum data rate?
Q1. A channel has a bandwidth of 20 MHz and uses QPSK modulation. What is the maximum data rate?
Answer: 80 Mbps
Explanation: QPSK has 2 bits per symbol, so C = 2 * B * 2 = 2 * 20 * 10^6 * 2 = 80 Mbps.