A signal is transmitted with a power of 100 mW. If it is attenuated by 20 dB, what is the received power?
Q1. A signal is transmitted with a power of 100 mW. If it is attenuated by 20 dB, what is the received power?
Answer: 1 mW
Explanation: Using the formula for dB, 20 dB = 10 log(P1/P2), so P2 = P1 / 10^(20/10) = 100 / 100 = 1 mW.