What is the maximum data rate of a channel with a bandwidth of 4 kHz and a signal-to-noise ratio of 10?
Q1. What is the maximum data rate of a channel with a bandwidth of 4 kHz and a signal-to-noise ratio of 10?
Answer: 80 kbps
Explanation: Using Shannon's theorem, C = B * log2(1 + S/N) = 4000 * log2(1 + 10) = 4000 * log2(11) = 4000 * 3.459 = 13836 bps or approximately 13.8 kbps, but closest answer is obtained using Nyquist theorem for max data rate, 2 * 4 kHz *.