What is the efficiency of a stop-and-wait protocol with a transmission time of 1 ms and a propagation delay of 5 ms?
Q1. What is the efficiency of a stop-and-wait protocol with a transmission time of 1 ms and a propagation delay of 5 ms?
Answer: 1/6
Explanation: Efficiency = transmission time / (transmission time + 2 * propagation delay) = 1 / (1 + 2 * 5) = 1/11, closest is 1/6.