engineering computer science MCQ #519

A sender using a stop-and-wait protocol has a timeout of 100 ms. If the round-trip time is 80 ms, what is the maximum throughput?

engineering computer science MCQ #519

  1. Question 1

    Q1. A sender using a stop-and-wait protocol has a timeout of 100 ms. If the round-trip time is 80 ms, what is the maximum throughput?

    • A) 1 / 18 packets per second
    • B) 1 / 10 packets per second
    • C) 10 packets per second
    • D) 5 packets per second

    Answer: 10 packets per second

    Explanation: Maximum throughput = 1 / (RTT + timeout - RTT) is not correct, instead, it is 1 / max(RTT, timeout), here it is 1 / 100 ms = 10 packets per second.