A person drives 6 km north, then 8 km east, and finally 2 km south. What is the shortest distance from the initial to the final position?
Q1. A person drives 6 km north, then 8 km east, and finally 2 km south. What is the shortest distance from the initial to the final position?
Answer: √(4² + 8²) km
Explanation: The person ends up 4 km north (6 km - 2 km) and 8 km east, so use Pythagoras theorem: √(4² + 8²).