A man drives 4 km north, then 3 km east, and finally 2 km south. What is the shortest distance from the initial to the final position?
Q1. A man drives 4 km north, then 3 km east, and finally 2 km south. What is the shortest distance from the initial to the final position?
Answer: √(2² + 3²) km
Explanation: The man ends up 2 km north (4 km - 2 km) and 3 km east, so use Pythagoras theorem: √(2² + 3²).