A person walks 5 km south, then 3 km east, then 2 km north. What is the shortest distance from the starting point?
Q1. A person walks 5 km south, then 3 km east, then 2 km north. What is the shortest distance from the starting point?
Answer: √(3² + 3²) km
Explanation: Net displacement south is 5 - 2 = 3 km, and east is 3 km, so use Pythagoras' theorem: √(3² + 3²).