A girl cycles 5 km north, then 2 km east, then 1 km south. What is the shortest distance from the starting point?
Q1. A girl cycles 5 km north, then 2 km east, then 1 km south. What is the shortest distance from the starting point?
Answer: √(4² + 2²) km
Explanation: Net displacement north is 5 - 1 = 4 km, and east is 2 km, so use Pythagoras' theorem: √(4² + 2²).