A man walks 3 km north, then 4 km east. What is the shortest distance from his initial to final position?
Q1. A man walks 3 km north, then 4 km east. What is the shortest distance from his initial to final position?
Answer: 5 km
Explanation: Using Pythagoras' theorem: √(3² + 4²) = √(9 + 16) = √25 = 5 km.