A man travels 6 km north, then 4 km east, and finally 2 km south. What is his distance from the starting point?
Q1. A man travels 6 km north, then 4 km east, and finally 2 km south. What is his distance from the starting point?
Answer: 2√5 km
Explanation: Net northward distance is 6 - 2 = 4 km, and 4 km east. Use Pythagoras' theorem: √(4² + 4²) is incorrect, correct is √(4² + 2²) = √20 = 2√5 km.