A building is 50 m high. The angle of elevation of its top from a point on the ground is 60°. Find the distance.
Q1. A building is 50 m high. The angle of elevation of its top from a point on the ground is 60°. Find the distance.
Answer: 50√3 / 3 m
Explanation: Using tan(60°) = opposite/adjacent = 50/x, so x = 50 / √3 = 50√3 / 3 m.