A tower stands on a hill. The angle of elevation of the top of the tower from the foot of the hill is 60°. If the height of the tower is 50m and the height of the hill is 20m, what is the distance from the foot of the hill to the point of observation?
Q1. A tower stands on a hill. The angle of elevation of the top of the tower from the foot of the hill is 60°. If the height of the tower is 50m and the height of the hill is 20m, what is the distance from the foot of the hill to the point of observation?
Answer: 50√3 / 3 m
Explanation: tan(60°) = (50 + 20) / distance. So, distance = 70 / √3 = 50√3 / 3 m (after rationalizing).