The angle of elevation of a jet plane from a point on the ground is 60°. After 10 seconds, the angle becomes 30°. If the jet is flying at a height of 2000√3 m, what is its speed?
Q1. The angle of elevation of a jet plane from a point on the ground is 60°. After 10 seconds, the angle becomes 30°. If the jet is flying at a height of 2000√3 m, what is its speed?
Answer: 400 m/s
Explanation: Using tan(60°) = 2000√3 / x and tan(30°) = 2000√3 / (x + d), we can find d. Speed = d / 10.