engineering mathematics MCQ #1519

∫sin³x cos x dx

engineering mathematics MCQ #1519

  1. Question 1

    Q1. ∫sin³x cos x dx

    • A) (1/4)sin⁴x + C
    • B) -(1/4)sin⁴x + C
    • C) (1/4)cos⁴x + C
    • D) -(1/4)cos⁴x + C

    Answer: (1/4)sin⁴x + C

    Explanation: Using substitution u = sin x, du = cos x dx, hence ∫u³ du = (1/4)u⁴ + C.