engineering mathematics MCQ #1523

∫x²e^x dx

engineering mathematics MCQ #1523

  1. Question 1

    Q1. ∫x²e^x dx

    • A) x²e^x - 2xe^x + 2e^x + C
    • B) x²e^x + 2xe^x + 2e^x + C
    • C) x²e^x - 2xe^x - 2e^x + C
    • D) x²e^x + 2xe^x - 2e^x + C

    Answer: x²e^x - 2xe^x + 2e^x + C

    Explanation: Using integration by parts twice, with u = x² and dv = e^x dx.