engineering mathematics MCQ #1534

∫1 / (√(x² - 4)) dx = ?

engineering mathematics MCQ #1534

  1. Question 1

    Q1. ∫1 / (√(x² - 4)) dx = ?

    • A) ln|x + √(x² - 4)| + C
    • B) ln|x - √(x² - 4)| + C
    • C) (1/2)ln|x² - 4| + C
    • D) sin-¹(x/2) + C

    Answer: ln|x + √(x² - 4)| + C

    Explanation: Using standard integral ∫1 / √(x² - a²) dx = ln|x + √(x² - a²)| + C, where a = 2.