engineering mathematics MCQ #1535

∫e^(2x)sinx dx = ?

engineering mathematics MCQ #1535

  1. Question 1

    Q1. ∫e^(2x)sinx dx = ?

    • A) (e^(2x)(2sinx - cosx))/5 + C
    • B) (e^(2x)(sinx + 2cosx))/5 + C
    • C) (e^(2x)(sinx - cosx))/2 + C
    • D) (e^(2x)sinx)/2 + C

    Answer: (e^(2x)(2sinx - cosx))/5 + C

    Explanation: Using integration by parts twice, with u = sinx and dv = e^(2x)dx, we get the required result.