engineering mathematics MCQ #1536

∫x² / (1 + x³) dx = ?

engineering mathematics MCQ #1536

  1. Question 1

    Q1. ∫x² / (1 + x³) dx = ?

    • A) (1/3)ln|1 + x³| + C
    • B) (1/2)ln|1 + x²| + C
    • C) (1/3)ln|1 + x| + C
    • D) x - (1/3)ln|1 + x³| + C

    Answer: (1/3)ln|1 + x³| + C

    Explanation: Using substitution u = 1 + x³, du/dx = 3x², hence ∫x² / (1 + x³) dx = (1/3)∫du/u = (1/3)ln|u| + C.