engineering mathematics MCQ #1537

∫1 / (x² + 4x + 8) dx = ?

engineering mathematics MCQ #1537

  1. Question 1

    Q1. ∫1 / (x² + 4x + 8) dx = ?

    • A) (1/2)tan-¹((x + 2)/2) + C
    • B) (1/4)ln|x² + 4x + 8| + C
    • C) tan-¹(x + 2) + C
    • D) (1/2)ln|x + 2| + C

    Answer: (1/2)tan-¹((x + 2)/2) + C

    Explanation: Completing the square in denominator, x² + 4x + 8 = (x + 2)² + 4, and using standard integral ∫1 / (u² + a²) du.