engineering mathematics MCQ #1543

∫(sinx + cosx) / (sinx - cosx) dx = ?

engineering mathematics MCQ #1543

  1. Question 1

    Q1. ∫(sinx + cosx) / (sinx - cosx) dx = ?

    • A) ln|sinx - cosx| + C
    • B) ln|sinx + cosx| + C
    • C) -ln|sinx - cosx| + C
    • D) x + ln|sinx - cosx| + C

    Answer: ln|sinx - cosx| + C

    Explanation: Using substitution u = sinx - cosx, du/dx = cosx + sinx, hence ∫(sinx + cosx) / (sinx - cosx) dx = ∫du/u = ln|u| + C.