engineering mathematics MCQ #1554

∫e^(x) sin(x) dx = ?

engineering mathematics MCQ #1554

  1. Question 1

    Q1. ∫e^(x) sin(x) dx = ?

    • A) (e^(x) (sin(x) - cos(x))) / 2 + C
    • B) e^(x) sin(x) + C
    • C) (e^(x) sin(x)) / 2 + C
    • D) (e^(x) cos(x)) / 2 + C

    Answer: (e^(x) (sin(x) - cos(x))) / 2 + C

    Explanation: Applied integration by parts twice, resulting in the formula ∫e^(x) sin(x) dx = (e^(x) (sin(x) - cos(x))) / 2 + C.