The top of a 15 m high tower makes an angle of elevation of 60° with the bottom of an electric pole. If the distance between them is 10√3 m, what is the height of the electric pole?
Q1. The top of a 15 m high tower makes an angle of elevation of 60° with the bottom of an electric pole. If the distance between them is 10√3 m, what is the height of the electric pole?
Answer: 20 m
Explanation: First, find the height difference using tan(60°) = height difference / 10√3. Then, subtract this from the tower height.