engineering mathematics MCQ #1567

∫x² sin(x) dx = ?

engineering mathematics MCQ #1567

  1. Question 1

    Q1. ∫x² sin(x) dx = ?

    • A) -x²cos(x) + 2∫xcos(x) dx
    • B) x²cos(x) + 2∫xcos(x) dx
    • C) -x²sin(x) + 2∫xsin(x) dx
    • D) x²sin(x) + 2∫xsin(x) dx

    Answer: -x²cos(x) + 2∫xcos(x) dx

    Explanation: Using integration by parts with u = x² and dv = sin(x) dx, we get du = 2x dx and v = -cos(x).