engineering mathematics MCQ #1578

∫x² sinx dx = ?

engineering mathematics MCQ #1578

  1. Question 1

    Q1. ∫x² sinx dx = ?

    • A) -x² cosx + 2x sinx + 2 cosx + C
    • B) -x² cosx + 2x sinx - 2 cosx + C
    • C) x² cosx + 2x sinx + 2 cosx + C
    • D) x² cosx - 2x sinx + 2 cosx + C

    Answer: -x² cosx + 2x sinx + 2 cosx + C

    Explanation: Using integration by parts twice, we arrive at the given solution.