engineering mathematics MCQ #1591

∫sin(x) dx from 0 to π = ?

engineering mathematics MCQ #1591

  1. Question 1

    Q1. ∫sin(x) dx from 0 to π = ?

    • A) 0
    • B) 1
    • C) 2
    • D) -1

    Answer: 2

    Explanation: The antiderivative of sin(x) is -cos(x). Evaluate from 0 to π: (-cos(π)) - (-cos(0)) = -(-1) - (-1) = 2.