engineering mathematics MCQ #177

If sin(A + B) = √3/2 and cos(A - B) = √3/2, then A + B + A - B = ?

engineering mathematics MCQ #177

  1. Question 1

    Q1. If sin(A + B) = √3/2 and cos(A - B) = √3/2, then A + B + A - B = ?

    • A) 60° + 30°
    • B) 90°
    • C) 120°
    • D) 150°

    Answer: 90°

    Explanation: Since sin(A + B) = √3/2, A + B = 60° and cos(A - B) = √3/2 gives A - B = 30°, hence A + B + A - B = 2A = 90°.