The distance of the point (1, 2) from the line 3x + 4y = 5 is
Q1. The distance of the point (1, 2) from the line 3x + 4y = 5 is
Answer: |3 + 8 - 5| / √(3² + 4²)
Explanation: Using distance formula: |Ax1 + By1 - C| / √(A² + B²) = |3*1 + 4*2 - 5| / √(3² + 4²)