engineering mathematics MCQ #1834

The center and radius of the circle x² + y² - 4x - 6y = 12 are

engineering mathematics MCQ #1834

  1. Question 1

    Q1. The center and radius of the circle x² + y² - 4x - 6y = 12 are

    • A) (2, 3), √25
    • B) (-2, -3), √25
    • C) (2, 3), √12
    • D) (-2, -3), √12

    Answer: (2, 3), √25

    Explanation: Completing the square: (x - 2)² + (y - 3)² = 12 + 4 + 9 = 25, so center is (2, 3) and radius is √25 = 5