engineering mathematics MCQ #1838

The equation of the hyperbola with foci (0, ±5) and transverse axis 8 is

engineering mathematics MCQ #1838

  1. Question 1

    Q1. The equation of the hyperbola with foci (0, ±5) and transverse axis 8 is

    • A) y² / 16 - x² / 9 = 1
    • B) y² / 9 - x² / 16 = 1
    • C) x² / 16 - y² / 9 = 1
    • D) x² / 9 - y² / 16 = 1

    Answer: y² / 16 - x² / 9 = 1

    Explanation: Using hyperbola equation: c² = a² + b², where c = 5, 2a = 8, so a = 4, b² = 25 - 16 = 9, and the equation is y² / 16 - x² / 9 = 1