The distance of the point (3, 4) from the line 3x + 4y = 5 is
Q1. The distance of the point (3, 4) from the line 3x + 4y = 5 is
Answer: 4 / 5
Explanation: Using the distance formula: |Ax1 + By1 - C| / √(A² + B²) = |3*3 + 4*4 - 5| / √(3² + 4²) = |9 + 16 - 5| / √(9 + 16) = 20 / 5 = 4