engineering mathematics MCQ #1853

The equation of the circle with diameter joining (1, 2) and (3, 4) is

engineering mathematics MCQ #1853

  1. Question 1

    Q1. The equation of the circle with diameter joining (1, 2) and (3, 4) is

    • A) (x - 2)² + (y - 3)² = 2
    • B) (x - 2)² + (y - 3)² = 4
    • C) (x - 1)² + (y - 2)² = 2
    • D) (x - 3)² + (y - 4)² = 2

    Answer: (x - 2)² + (y - 3)² = 2

    Explanation: The center is the midpoint (2, 3) and radius is half the distance between the points, which is √2, so the equation is (x - 2)² + (y - 3)² = 2