The distance of the point (1, 2) from the line 3x + 4y + 5 = 0 is
Q1. The distance of the point (1, 2) from the line 3x + 4y + 5 = 0 is
Answer: 12/5
Explanation: Using the distance formula: |Ax1 + By1 + C|/√(A² + B²), where A = 3, B = 4, C = 5, (x1, y1) = (1, 2).