engineering mathematics MCQ #1872

The equation of the hyperbola with transverse axis 6 and conjugate axis 8 is

engineering mathematics MCQ #1872

  1. Question 1

    Q1. The equation of the hyperbola with transverse axis 6 and conjugate axis 8 is

    • A) x² / 9 - y² / 16 = 1
    • B) x² / 16 - y² / 9 = 1
    • C) y² / 9 - x² / 16 = 1
    • D) y² / 16 - x² / 9 = 1

    Answer: x² / 9 - y² / 16 = 1

    Explanation: The general equation of a hyperbola is x² / a² - y² / b² = 1, where a and b are semi-transverse and semi-conjugate axes.