engineering mathematics MCQ #1877

The coordinates of the foci of the hyperbola x²/9 - y²/16 = 1 are

engineering mathematics MCQ #1877

  1. Question 1

    Q1. The coordinates of the foci of the hyperbola x²/9 - y²/16 = 1 are

    • A) (±5, 0)
    • B) (±4, 0)
    • C) (0, ±5)
    • D) (0, ±4)

    Answer: (±5, 0)

    Explanation: For hyperbola x²/a² - y²/b² = 1, the foci are (±√(a² + b²), 0) = (±√(9 + 16), 0) = (±5, 0).