engineering mathematics MCQ #1882

The equation of the hyperbola with center (0, 0) and transverse axis along x-axis is

engineering mathematics MCQ #1882

  1. Question 1

    Q1. The equation of the hyperbola with center (0, 0) and transverse axis along x-axis is

    • A) x²/a² + y²/b² = 1
    • B) x²/a² - y²/b² = 1
    • C) y²/a² - x²/b² = 1
    • D) y²/a² + x²/b² = 1

    Answer: x²/a² - y²/b² = 1

    Explanation: The standard equation of a hyperbola with transverse axis along the x-axis is x²/a² - y²/b² = 1.