The upper 3/4th portion of a vertical pole subtends an angle θ such that tan θ = 3 / 5√3 at a point in the horizontal plane through its foot and at a distance 40 m from the foot. What is the height of the pole?
Q1. The upper 3/4th portion of a vertical pole subtends an angle θ such that tan θ = 3 / 5√3 at a point in the horizontal plane through its foot and at a distance 40 m from the foot. What is the height of the pole?
Answer: 50 m
Explanation: Using the tangent function for the angle subtended by the upper portion and the given distance, we can derive the height of the pole.