The angle of elevation of the top of a tower from a point 100 m away is 30°. Find the height of the tower.
Q1. The angle of elevation of the top of a tower from a point 100 m away is 30°. Find the height of the tower.
Answer: 100√3 m
Explanation: Using tan(30°) = height / 100, we get height = 100 * tan(30°) = 100 / √3 * √3 / √3 = 100√3 / 3, simplifying we use tan(30°) = 1/√3.