A surveyor measures the angle of elevation to the top of a building as 60°. If the building is 30 m high, how far is the surveyor from the building?
Q1. A surveyor measures the angle of elevation to the top of a building as 60°. If the building is 30 m high, how far is the surveyor from the building?
Answer: 30 / √3 m
Explanation: Using tan(60°) = 30 / distance, we get distance = 30 / tan(60°) = 30 / √3 = 30 / √3 * (√3 / √3) = 30√3 / 3 = 10√3 m.