A tree is observed from two positions, A and B, which are 100 m apart. The angle of elevation to the top from A is 30° and from B is 45°. What is the height of the tree?
Q1. A tree is observed from two positions, A and B, which are 100 m apart. The angle of elevation to the top from A is 30° and from B is 45°. What is the height of the tree?
Answer: 50(√3 + 1) m
Explanation: Using the tangent function, we can form two equations with the height of the tree and the distance from A and B to the tree. Solving these equations simultaneously gives the height as 50(√3 + 1) m, utilizing the formula tan(angle) = opposite/adjacent.