engineering mathematics MCQ #333

The vertices of the hyperbola 9x² - 16y² = 144 are

engineering mathematics MCQ #333

  1. Question 1

    Q1. The vertices of the hyperbola 9x² - 16y² = 144 are

    • A) (±4, 0)
    • B) (0, ±4)
    • C) (±3, 0)
    • D) (0, ±3)

    Answer: (±4, 0)

    Explanation: For x² / a² - y² / b² = 1, vertices = (±a, 0).