engineering mathematics MCQ #338

The radius of the circle x² + y² - 4x + 6y + 4 = 0 is

engineering mathematics MCQ #338

  1. Question 1

    Q1. The radius of the circle x² + y² - 4x + 6y + 4 = 0 is

    • A) 3
    • B) √3
    • C) √7
    • D) √13

    Answer: 3

    Explanation: Radius = √(g² + f² - c) for x² + y² + 2gx + 2fy + c = 0.