engineering mathematics MCQ #339

What is the center of the circle given by x² + y² - 4x + 6y + 9 = 0?

engineering mathematics MCQ #339

  1. Question 1

    Q1. What is the center of the circle given by x² + y² - 4x + 6y + 9 = 0?

    • A) (2, 3)
    • B) (2, -3)
    • C) (-2, 3)
    • D) (-2, -3)

    Answer: (2, -3)

    Explanation: Complete the square: (x-2)² + (y+3)² = 4. Center at (2, -3).