engineering mathematics MCQ #362

Vertices at (±3, 0) and foci at (±5, 0) define a hyperbola:

engineering mathematics MCQ #362

  1. Question 1

    Q1. Vertices at (±3, 0) and foci at (±5, 0) define a hyperbola:

    • A) x²/16 - y²/9 = 1
    • B) x²/9 - y²/16 = 1
    • C) x²/25 - y²/9 = 1
    • D) y²/9 - x²/16 = 1

    Answer: x²/9 - y²/16 = 1

    Explanation: c² = a² + b² ⇒ 25 = 9 + 16. Use x²/a² - y²/b² =1.