engineering mathematics MCQ #381

What are the foci of the hyperbola y²/9 - x²/16 = 1?

engineering mathematics MCQ #381

  1. Question 1

    Q1. What are the foci of the hyperbola y²/9 - x²/16 = 1?

    • A) (±5, 0)
    • B) (0, ±5)
    • C) (±4, 0)
    • D) (0, ±4)

    Answer: (0, ±5)

    Explanation: c² = a² + b² = 9 + 16 = 25 ⇒ c=5. Foci at (0, ±5).